Bug 11498

Summary: bash does not honour set -e in subshells
Product: [Retired] Red Hat Linux Reporter: rjb
Component: bashAssignee: Bernhard Rosenkraenzer <bero>
Status: CLOSED RAWHIDE QA Contact:
Severity: medium Docs Contact:
Priority: medium    
Version: 6.1   
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OS: Linux   
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Last Closed: 2000-05-18 09:08:19 UTC Type: ---
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Description rjb 2000-05-18 09:08:19 UTC 
For both 1.14.7(1) and 2.03.6(1)-release bash does not honous set -e
in subshells.  Consider this:

$ echo $BASH_VERSION
1.14.7(1)
$ (set -e; echo 1; false; echo 2) || echo 3
1
2
$ sh -c "set -e; echo 1; false; echo 2" || echo 3
1
3
$ bash2 -c "set -e; echo 1; false; echo 2" || echo 3
1
3
$ bash -c "set -e; echo 1; false; echo 2" || echo 3
1
3
$ bash2
$ echo $BASH_VERSION
2.03.6(1)-release
$ (set -e; echo 1; false; echo 2) || echo 3
1
2
$

Bash should behave in () correctly.  The correct answer is 1 3
Comment 1 Bernhard Rosenkraenzer 2000-08-04 11:29:57 UTC 
Fixed in 2.04-8