Bug 166736

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User-Agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.7.8) Gecko/20050511

Description of problem:
std::showbase combined with std::hex in <iostream> fails to show the base if the value is 0. The following program should produce "0x0" as the output in all lines which start with:
std::cout << std::hex << std::showbase...

Instead this program produces output "0", skipping the "0x" base.

// main.cxx
#include <iostream>

int main()
{
   unsigned int var = 0;
   std::cout << var << "\n";

   // This is a failure line, it outputs "0" instead of "0x0".
   std::cout << std::hex << std::showbase << var << "\n";

   var = 1;
   std::cout << var << "\n";
   std::cout << std::hex << std::showbase << var << "\n";

   return 0;
}


Version-Release number of selected component (if applicable):


How reproducible:
Always

Steps to Reproduce:
1. Use std::hex and std::showbase in a std::cout, then feed 0 to the stream.
  

Actual Results:  Outputs "0".

Expected Results:  Outputs "0x0".

Additional info:

gcc-c++-4.0.1-4.fc4