Bug 169420

Description of problem:
"
#!/bin/bash

# The point of this program is to find out why the calls to exit in
# debugcore++.sh does not work.

# Answer: If the shell function is called using back quotes, it won't
# be able to exit the whole program.

function pleaseExit () {
    echo monkey
    exit
}

MONKEY=$(pleaseExit)
echo pleaseExit did not exit but returned: \"$MONKEY\"

# If we get here, something is wrong
exit 1
"

Version-Release number of selected component (if applicable):
All I have tried.  For example:
bash-3.0-19.2

How reproducible:
Every time

Steps to Reproduce:
1. Write a script with a function that does "exit".
2. Call the function using $(), i.e. FOO=$(yourFunction)
  
Actual results:
The script doesn't terminate.

Expected results:
The script should have terminated.

Additional info:
I have searched for information about this, but the only things I've managed to
come up with are indications that this should work as I expect:

Quoting the man page:
"Functions are executed in the context of the current shell; no new process is
created to interpret them".  Shouldn't this mean that "exit" should exit the
current shell?

There is a "return" command for returning from a function with a result code.
Why have "exit" do the same thing?

Doing "exit" in a function works as expected if you call the function without
$().  Why not with $()?