Bug 680085

Summary: Udisks leaks __udisks () function to interactive shell
Product: Red Hat Enterprise Linux 6 Reporter: David Jaša <djasa>
Component: udisksAssignee: David Zeuthen <davidz>
Status: CLOSED NOTABUG QA Contact: desktop-bugs <desktop-bugs>
Severity: low Docs Contact:
Priority: low    
Version: 6.2CC: mclasen, tpelka
Target Milestone: rc   
Target Release: ---   
Hardware: Unspecified   
OS: Unspecified   
Whiteboard:
Fixed In Version: Doc Type: Bug Fix
Doc Text:
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Clone Of: Environment:
Last Closed: 2011-02-26 22:11:45 UTC Type: ---
Regression: --- Mount Type: ---
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Verified Versions: Category: ---
oVirt Team: --- RHEL 7.3 requirements from Atomic Host:
Cloudforms Team: --- Target Upstream Version:

Description David Jaša 2011-02-24 10:29:47 UTC
Description of problem:


Version-Release number of selected component (if applicable):
udisks-1.0.1-2.el6.x86_64

How reproducible:


Steps to Reproduce:
1. run terminal
2. type command:
typeset -f
3. 
  
Actual results:
function __udisks () { $lot_of_if's; } is printed

Expected results:
no function should be there unless defined in shell profile or rc file

Additional info: 
* RHEL 6 nightly
* function is defined in /etc/profile.d/udisks-bash-completion.sh

Comment 2 RHEL Program Management 2011-02-24 10:57:53 UTC
This request was evaluated by Red Hat Product Management for
inclusion in the current release of Red Hat Enterprise Linux.
Because the affected component is not scheduled to be updated
in the current release, Red Hat is unfortunately unable to
address this request at this time. Red Hat invites you to
ask your support representative to propose this request, if
appropriate and relevant, in the next release of Red Hat
Enterprise Linux. If you would like it considered as an
exception in the current release, please ask your support
representative.

Comment 3 David Zeuthen 2011-02-24 15:52:05 UTC
(In reply to comment #0)
> Description of problem:
> 
> 
> Version-Release number of selected component (if applicable):
> udisks-1.0.1-2.el6.x86_64
> 
> How reproducible:
> 
> 
> Steps to Reproduce:
> 1. run terminal
> 2. type command:
> typeset -f
> 3. 
> 
> Actual results:
> function __udisks () { $lot_of_if's; } is printed
> 
> Expected results:
> no function should be there unless defined in shell profile or rc file

I don't agree with this. Why do you think this is so?

> Additional info: 
> * RHEL 6 nightly
> * function is defined in /etc/profile.d/udisks-bash-completion.sh

That file is there so completion on the udisks(1) command works out of the box.

Comment 4 David Jaša 2011-02-24 23:34:13 UTC
I should have noted that the bash-completion is not even installed on the system in question. Looking at the contents of bash-completion package, it seems that program-specific functions are stored either in /etc/bash-completion.d/ or in /usr/share/bash-completion/ .

Comment 5 David Zeuthen 2011-02-26 22:11:45 UTC
It doesn't matter if bash-completion (which is just a collection of random completion snippets) is installed; the intent is for the udisks(1) bash completion to work regardless (just like it does for files and other things). Don't worry, it's a common mistake to assume this. I'm closing this as NOTABUG.