Bug 749167

The line reads:

> if (open(CHILD, "-|") == 0) {

What is it? The open is missing third argument. perldoc -f open says:

> For three or more arguments if MODE is '|-', the filename is
> interpreted as a command to which output is to be piped, and if
> MODE is '-|', the filename is interpreted as a command that
> pipes output to us.  In the two-argument (and one-argument)
> form, one should replace dash ('-') with the command.  See
> "Using open() for IPC" in perlipc for more examples of this.

However I cannot reproduce it. Maybe I have to much memory. However I noticed an defunct child and zombie before init cleaned it, so there is something wrong definitely.

(In reply to comment #1)
> The line reads:
> 
> > if (open(CHILD, "-|") == 0) {
> 
> What is it? The open is missing third argument. perldoc -f open says:
> 
> > For three or more arguments if MODE is '|-', the filename is
> > interpreted as a command to which output is to be piped, and if
> > MODE is '-|', the filename is interpreted as a command that
> > pipes output to us.  In the two-argument (and one-argument)
> > form, one should replace dash ('-') with the command.  See
> > "Using open() for IPC" in perlipc for more examples of this.

I cannot speak for this bugzilla as a whole but the open is not missing any argument -- see man perlipc for what open(CHILD, "-|") means.

I see, the sentence 

> In the two-argument (and one-argument) form, one should replace dash ('-')
> with the command.

is just an example for one case. All cases are described in perlipc. Thank you.

So it should mkpipe(2) and fork(2) and dup(2) to read output of forked of itself. It seems there is not enough memory for fork.

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