Bug 890185

Summary: postgres support for database
Product: Red Hat OpenStack Reporter: Perry Myers <pmyers>
Component: openstack-swiftAssignee: RHOS Maint <rhos-maint>
Status: CLOSED NOTABUG QA Contact: Yaniv Kaul <ykaul>
Severity: medium Docs Contact:
Priority: medium    
Version: 1.0 (Essex)CC: apevec, jkt, markmc, zaitcev
Target Milestone: gaKeywords: FutureFeature, TestOnly
Target Release: 2.1   
Hardware: Unspecified   
OS: Unspecified   
Whiteboard:
Fixed In Version: Doc Type: Enhancement
Doc Text:
Story Points: ---
Clone Of: 816316 Environment:
Last Closed: 2013-01-07 21:39:42 UTC Type: Bug
Regression: --- Mount Type: ---
Documentation: --- CRM:
Verified Versions: Category: ---
oVirt Team: --- RHEL 7.3 requirements from Atomic Host:
Cloudforms Team: --- Target Upstream Version:
Embargoed:
Bug Depends On:    
Bug Blocks: 816316    

Description Perry Myers 2012-12-25 15:11:22 UTC
+++ This bug was initially created as a clone of Bug #816316 +++

Description of problem:
Presently upstream OpenStack primarily utilizes mysql for its database.  We'd like to expand this to include postgres in addition.  There are probably some integration issues/small problems with running Postgres w/ Essex today, and these bugs will need to be tracked and individually resolved separately.

This bug is specifically for tracking the overall support of Postgres, and as such is a TestOnly bug.

--- Additional comment from Perry Myers on 2012-04-25 15:14:39 EDT ---

Related bugs:
https://bugs.launchpad.net/glance/+bug/953159
https://bugs.launchpad.net/glance/+bugs?field.tag=postgresql

Comment 1 Pete Zaitcev 2013-01-07 19:25:56 UTC
But Perry, Swift does not use OpenStack's main database, except indirectly
through Keystone. What is it that I need to do here, specifically?
Verify that Keystone auth works in Swift when backend is Postgres?

Comment 2 Perry Myers 2013-01-07 19:27:26 UTC
If Swift doesn't use a database at all, then this bug can be closed as NOTABUG, so just go ahead and do that.  I wasn't aware that Swift didn't use a database in any fashion