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Bug 1867755

Summary:	unable to use zipl default timeout
Product:	Red Hat Enterprise Linux 8	Reporter:	Qian Cai <qcai>
Component:	s390utils	Assignee:	Dan Horák <dhorak>
Status:	CLOSED WORKSFORME	QA Contact:	Kernel-QE - Hardware <kernel-qe-hw>
Severity:	medium	Docs Contact:
Priority:	medium
Version:	8.3	Flags:	pm-rhel: mirror+
Target Milestone:	rc
Target Release:	8.0
Hardware:	s390x
OS:	Linux
Whiteboard:
Fixed In Version:		Doc Type:	If docs needed, set a value
Doc Text:		Story Points:	---
Clone Of:		Environment:
Last Closed:	2020-08-17 12:23:55 UTC	Type:	Bug
Regression:	---	Mount Type:	---
Documentation:	---	CRM:
Verified Versions:		Category:	---
oVirt Team:	---	RHEL 7.3 requirements from Atomic Host:
Cloudforms Team:	---	Target Upstream Version:
Embargoed:

Description Qian Cai 2020-08-10 17:01:32 UTC

Description of problem:
Default zipl.conf has timeout=5, but that is not enough time to switch to a different kernel due to for example, boot failures from a debug kernel, i.e., typing "#cp vi vmsg" from the serial console takes longer than 5 seconds.

Version-Release number of selected component (if applicable):
s390utils-base-2.6.0-28.el8.s390x

Comment 1 Dan Horák 2020-08-17 12:23:55 UTC

Closing, we don't want to extend the boot times. I have managed to type the #cp ... command fast enough so it's doable :-) Also you can copy&paste a prepared text.