The script that starts vnc-server makes a call to another script that does
the actual executing of VNC.  However, this script spawns a child process
that is the vnc server.  Because the name of the executable
changes.pidlist=`pidofproc $1`
Example:
(from /etc/init.d/functions)
<snip>
        # Save basename.
        base=`basename $1`

        # Find pid.
        pid=
        for apid in $pidlist ; do
           [ -d /proc/$apid ] && pid="$pid $apid"
        done
</snip>

The basename of /usr/bin/vncserver is vncserver, while the actual
executable is Xvnc.  Note that Xvnc isn't the client (thats vncviewer). 
The only implication I've seen so far is that while trying to query the
status of vncserver or kill/restart it, the script fails, not only not
returning the status, but not killing the server.  If the server has an
another attempt to start before a reboot or manual removal of the Xvnc
process, the new instances cannot grab the default :0 or :1 addresses and
therefore may lead to confusion as to which Xvnc session is being accessed.

-Ben Klang, KF4WBX
ben