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Description of problem:
# this works
$ x=$(for i in test; do echo $i; done)
$ echo $x
test
# this too, works
$ i=test
$ x=$(case $i in test) echo test;; esac)
$ echo $x
test
# this does not
$ x=$(for i in test; do case $i in test) echo test;; esac; done)
-bash: syntax error near unexpected token `;;'
# however removing the output-into-variable makes it work
$ (for i in test; do case $i in test) echo test;; esac; done)
test
Version-Release number of selected component (if applicable):
bash-4.2.46-12.el7
How reproducible:
always
Actual results:
expression fails on syntax error
Expected results:
the subshell output is assigned to a variable
Additional info:
This *works* on my bash-4.3.30-2.fc21, so there might have been an upstream fix.
Hi Jiri,
Yes, this was fixed in 4.3. I have yet to look at the size of the change.
Meanwhile, the more verbose way of writing a case statement still seems to work:
x=$(for i in test; do case $i in (test) echo test;; esac; done)
# ^^
Since the problem described in this bug report should be
resolved in a recent advisory, it has been closed with a
resolution of ERRATA.
For information on the advisory, and where to find the updated
files, follow the link below.
If the solution does not work for you, open a new bug report.
https://rhn.redhat.com/errata/RHBA-2015-2144.html