Bug 1241021

zsh in RHEL 6 has the same issue. Additionally, this code:
x=$(case $i in test) echo test;; esac) which works in bash, doesn't work in zsh

Version-Release number of selected component (if applicable):
zsh-4.3.11-4.el6

+++ This bug was initially created as a clone of Bug #1212775 +++

Description of problem:

# this works
$ x=$(for i in test; do echo $i; done)
$ echo $x
test

# this too, works
$ i=test
$ x=$(case $i in test) echo test;; esac)
$ echo $x
test

# this does not
$ x=$(for i in test; do case $i in test) echo test;; esac; done)
-bash: syntax error near unexpected token `;;'

# however removing the output-into-variable makes it work
$ (for i in test; do case $i in test) echo test;; esac; done)
test


Version-Release number of selected component (if applicable):
bash-4.2.46-12.el7

How reproducible:
always

Actual results:
expression fails on syntax error

Expected results:
the subshell output is assigned to a variable

Additional info:
This *works* on my bash-4.3.30-2.fc21, so there might have been an upstream fix.

--- Additional comment from Ondrej Oprala on 2015-04-18 09:36:45 EDT ---

Hi Jiri,
Yes, this was fixed in 4.3. I have yet to look at the size of the change.

Meanwhile, the more verbose way of writing a case statement still seems to work:
x=$(for i in test; do case $i in (test) echo test;; esac; done)
#                                ^^