Bug 105348

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User-Agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.4.1) Gecko/20030906

Description of problem:
A call to close() sets a wrong value of the pthread cancellation type while a
call to pthread_setcanceltype() fixes this value.

We have two systems, one machine is running on a i586 CPU and the other machine
is running on a i686 dual CPU configuration. The installation is a Red Hat Linux
8.0 with the updated glibc 2.3.2.

 * The Kernel on the i586 system is the default kernel from the CD 
 * The kernel on the i686 system is the latest available kernel
   found on Red Hat's FTP site.
 * The glibc on the i686 system is for the i686 architecture
 * The the glibc on the i586 system is for the i386 architecture

The behaviour of the sample program is differently on both systems. On the i586
system it is incorrect, and on the i686 system it is correct as long as the
environment variable LD_ASSUME_KERNEL is not set to 2.2.5 or tho 2.4.0. When it
is set, it behaves the same as on the i586 system (ie it demonstrates the bug).
However we were able to reproduce the problem on another i686 machine as well,
without setting the environment variable LD_ASSUME_KERNEL, but the application
we were running there is not quite as simple as the attached sample program.

Note that the sample program works fine on a default glibc which
ships with Red Hat Linux 8.0 (glibc 2.2.93) on both machines.


Version-Release number of selected component (if applicable):
glibc-common-2.3.2-4.80.6

How reproducible:
Always

Steps to Reproduce:
1. Compile the appended example program using the Makefile

2. Execute the binary on an unpatched RH 8.0 system with glibc 2.2.9x

3. Execute the binary on a patched RH 8.0 system with glibc 2.3.2

Actual Results:  Incorrect output (glibc 2.3.2):

creating new thread thread_id = 0
B0 rc=0 new=0  old=0
B1 rc=0 new=0  old=40
error: 0 Success
B2 rc=22 new=40  old=40
B3 rc=0 new=0  old=0
thr func end


Expected Results:  Correct output (glibc 2.2.9x):

creating new thread thread_id = 0
B0 rc=0 new=0  old=0
B1 rc=0 new=0  old=0
B2 rc=0 new=0  old=0
B3 rc=0 new=0  old=0
thr func
thr func end


Additional info: