Bug 130735 - strsep() function usage ends with "Segmentation fault"
strsep() function usage ends with "Segmentation fault"
Status: CLOSED NOTABUG
Product: Fedora
Classification: Fedora
Component: glibc (Show other bugs)
2
i386 Linux
medium Severity medium
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Assigned To: Jakub Jelinek
Brian Brock
https://www.223-223.ru/svn/repos/phon...
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Depends On:
Blocks:
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Reported: 2004-08-23 21:45 EDT by Evgeny Sizikov
Modified: 2007-11-30 17:10 EST (History)
0 users

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Doc Type: Bug Fix
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Last Closed: 2004-08-30 11:07:03 EDT
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Description Evgeny Sizikov 2004-08-23 21:45:12 EDT
Description of problem:
with usage of strsep() function an entire program ends with
"Segmentation fault"

Version-Release number of selected component (if applicable):
glibc-2.3.3-27

How reproducible:
Compile and run the program given by the URL

Steps to Reproduce:
1. get the source from the URL
2. compile
3. run
  
Actual results:
testing strtok_r()...
AL=a
o=I
testing strsep()...
AL=a
o=I
Segmentation fault

Expected results:
all from above but without "Segmentation fault"

Additional info:
kernel-2.6.7-1.494.2.2 and gcc-3.3.3-7 was used to compile the test
program, hardware:
CPU AMD AthlonXP 2200+, MB Epox with nForce2-Ultra chipset, 2 DIMMs at
2-channel mode
Comment 1 Evgeny Sizikov 2004-08-23 21:51:24 EDT
Ah, yes - if strsep() finds no any of the separators provided in the
working buffer, it doesn't produces "Segmentation fault"
Comment 2 Jakub Jelinek 2004-08-30 11:07:03 EDT
Your testcase is wrong.
The segfault is not in strsep, but when trying to free(buf).
As you used buf as strtok_r's *ptrptr pointer (and data as strsep's *stringp
pointer), the buf you pass to free is what malloc gave you plus
8 (length of the test string) and data will be NULL at the end.
You probably want to change dataptr from char ** to char * and pass
&dataptr to strtok_r and strsep.

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