Red Hat Bugzilla – Bug 1459253
Bash consume exit code when keword "local" is used.
Last modified: 2017-06-12 22:36:33 EDT
Created attachment 1285465 [details] Reproducer Description of problem: x=$(echo 33; exit 33) returns exit code 33, but local x=$(echo 33; exit 33) returns 0 Version-Release number of selected component (if applicable): bash-4.3.43-4.fc25.x86_64 4.3.43(1)-release How reproducible: reproducer attached Actual results: bash-4.3.43-4.fc25.x86_64 GNU bash, version 4.3.43(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2013 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html> This is free software; you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. f1: 0 x= f2: 33 x=33 Invalid Expected results: f1 and f2 produce same output Additional info:
Do you wish to report this bug for RHEL 5 or Fedora ? I see that you are running Fedora packages on your system. Also, is there something missing from your reproducer steps ? local keyword can be used only within functions. Please provide a full reproducer.
(In reply to Jakub Prokeš from comment #0) > local x=$(echo 33; exit 33) This is a known programming mistake in your code, not a bug in the interpreter: https://github.com/koalaman/shellcheck/wiki/SC2155