Bug 149214 - #defined (linux) macro not supported when program compiled in ANSI mode
#defined (linux) macro not supported when program compiled in ANSI mode
Product: Red Hat Enterprise Linux 3
Classification: Red Hat
Component: glibc (Show other bugs)
i686 Linux
medium Severity medium
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Assigned To: Jakub Jelinek
Brian Brock
Depends On:
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Reported: 2005-02-21 07:09 EST by Tushar Telichari
Modified: 2007-11-30 17:07 EST (History)
1 user (show)

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Fixed In Version:
Doc Type: Bug Fix
Doc Text:
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Clone Of:
Last Closed: 2005-02-21 07:20:49 EST
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RHEL 7.3 requirements from Atomic Host:
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Attachments (Terms of Use)
Test case to reproduce the bug (203 bytes, text/plain)
2005-02-21 07:11 EST, Tushar Telichari
no flags Details

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Description Tushar Telichari 2005-02-21 07:09:08 EST
Description of problem: #defined (linux) macro not supported when program is
compiled in ANSI mode.

Version-Release number of selected component (if applicable):
gcc - 3.2.3-49
glibc - 2.3.2-95.30

How reproducible:

Steps to Reproduce:
1. g++ -ansi ansi.cpp
2. ./a.out
Actual results:
Not defined

Expected results:

Additional info:
works properly when compiled with - g++ ansi.cpp
Comment 1 Tushar Telichari 2005-02-21 07:11:16 EST
Created attachment 111251 [details]
Test case to reproduce the bug
Comment 2 Tushar Telichari 2005-02-21 07:19:33 EST
This macro is being used at many places in our product. Substituting the
#defined (linux) with something else is not a feasible solution. This problem is
seen when the code is compiled in ANSI mode. Could you please suggest a way to
make this macro available (besides sending -Dlinux during make) ?
Comment 3 Jakub Jelinek 2005-02-21 07:20:49 EST
That's on purpose, since linux macro violates the ISO C89/C99/C++98 namaspace.
A conforming ISO C89/C99/C++98 program can e.g. be
int linux;
or void linux (void) {}
See e.g. info gcc, search for -ansi.
You can use __linux or __linux__ macros instead.

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