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Description of problem:
'ipsec show' command does not work in platform-python (Python3)

Version-Release number of selected component (if applicable):
libreswan-3.27-7.el8.x86_64
RHEL-8.0.0-20190404.2

How reproducible:
100%

Steps to Reproduce:
    ipsec show

Actual results:
  File "/usr/libexec/ipsec/show", line 52
    print "Need to find matching IPsec policy for %s/32 <=> %s/32"%(source,dest)
                                                                 ^
SyntaxError: invalid syntax

Expected results:
no python error 

Additional info:
    head -n 1 /usr/libexec/ipsec/show
#! /usr/libexec/platform-python

    /usr/libexec/platform-python --version
Python 3.6.8

Hi Paul,

it's not fixed.

# rpm -q libreswan
libreswan-3.29-3.el8.x86_64

# ipsec show
  File "/usr/libexec/ipsec/show", line 52
    print "Need to find matching IPsec policy for %s/32 <=> %s/32" % (source, dest)
                                                                 ^
SyntaxError: invalid syntax

There are couple of other things in the source code. Please use 2to3. It's not a perfect tool, but it can give you hint what else needs to be fixed.

Since the problem described in this bug report should be
resolved in a recent advisory, it has been closed with a
resolution of ERRATA.

For information on the advisory, and where to find the updated
files, follow the link below.

If the solution does not work for you, open a new bug report.

https://access.redhat.com/errata/RHSA-2019:3391