Description of problem:
I'm trying to compile rhpl on another platform, and it uses a non-GNU make.  Using gmake fixes this, but the Makefile explicitly specifies 'make' rather than the traditional $(MAKE).  A patch is included below.

Version-Release number of selected component (if applicable):
0.216

How reproducible:
always

Steps to Reproduce:
1. run make
2. it fails
  
Actual results:


Expected results:


Additional info:
diff -ru rhpl-0.216/Makefile rhpl-0.216-mod//Makefile
--- rhpl-0.216/Makefile Fri Jun 13 11:07:58 2008
+++ rhpl-0.216-mod//Makefile    Fri Aug  8 11:03:02 2008
@@ -14,16 +14,16 @@
 all: subdirs

 subdirs:
-       for d in $(SUBDIRS); do make -C $$d; [ $$? = 0 ] || exit 1; done
+       for d in $(SUBDIRS); do $(MAKE) -C $$d; [ $$? = 0 ] || exit 1; done

 clean:
-       for d in $(SUBDIRS); do make -C $$d clean; done
+       for d in $(SUBDIRS); do $(MAKE) -C $$d clean; done
        rm -f *.o *.so *.lo *.a *.pyc

 install: all
        mkdir -p $(DESTDIR)/$(PYDIR)

-       for d in $(SUBDIRS); do make -C $$d install; done
+       for d in $(SUBDIRS); do $(MAKE) -C $$d install; done

        $(PYTHON) -c "import compileall; compileall.compile_dir('$(DESTDIR)/$(PYDIR)', 3, '$(PYDIR)', 1)"