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Description of problem:
See code:

class A
{
public:
    template<typename T>
    int f()
    {
        return 0;
    }
};

class B
{
    A a;
public:
    int g()
    {
        return a.f<int>(); //this works
    }

    template<typename U>
    int h()
    {
        return a.f<int>(); //this doesn't
    }
};


How reproducible:
Always

Steps to Reproduce:
1.  Compile above code (no special compiler switches necessary).
2.  See error


Actual Results:  testgcctemplatebug.cpp: In method `int B::h ()':
testgcctemplatebug.cpp:23: parse error before `>'


Expected Results:  Code would compile.

Additional info:

If you make A::f into a static function (and call it using "A::f" syntax),
or a global function, it works.  Even stranger, if you make a global
function f which is defined the same as the member function, but you still
call the member function version from B::g, it works.

If you give f an argument of type T*, and you instantiate the template
based on the argument rather than manually specifying the type, that works
too.  For now, I am working around the bug by allowing a dummy template
argument to be used to instatiate the template.

I suppose I am not entirely sure if the above code is valid C++, but the
only other compiler I could test on is MSVC.  Needless to say, it won't
compile the code either.  But that doesn't mean much, now does it?  :)

I am using gcc 2.96-85.