Created attachment 437726 [details]
DNS LDIF Example

Description of problem:
Latest version of bind-dyndb-ldap does not work with subdomains that are configured in ldap. Main domain (i.e. example.com) is loaded fine:
------------------------------------------------
querying 'idnsName=example.com,ou=Dynamic,ou=DNS,ou=Sluzby,dc=example,dc=com' with '(objectClass=idnsRecord)'
entry count: 1
------------------------------------------------

but all subdomains are loaded with errors:
------------------------------------------------
querying 'idnsName=srv, idnsName=example.com,ou=Dynamic,ou=DNS,ou=Sluzby,dc=example,dc=com' with '(objectClass=idnsRecord)'
entry count: 1
zone srv.example.com/IN: has 0 SOA records
zone srv.example.com/IN: not loaded due to errors.
------------------------------------------------

Complete example is in attachment. Subdomain (srv.example.com) is configured as record (idnsName=srv) in main domain (example.com) with NS records and also is placed in DNS container (like main domain) with SOA, NS records in object and classic zone records as subtree. 

Version-Release number of selected component (if applicable):
bind-dyndb-ldap-0.1.0-0.9.a1.20091210git.fc13.x86_64
bind-9.7.1-2.P2.fc13.x86_64
openldap-2.4.21-9.fc13.x86_64

How reproducible:
always

Steps to Reproduce:
1. import attachment
2. configure ldap section in named.conf to correct LDAP subtree
3. restart named
4. try to query pdc.srv.example.com
  
Actual results:
return code of query is SERVFAIL

Expected results:
return code of query should be NOERROR


query of record ares.example.com will succeeded.

Additional info:
With version bind-dyndb-ldap-0.1.0-0.5.a1.fc13.x86_64 (recompliled from fc12) everything works fine:
zone srv.example.com/IN: sending notifies (serial 2009083001)

I do no if the DNS structure in LDAP was changed, bud I could not find any info about changes. I am using latest schema distributed with last version of bind-dyndb-ldap. Subtree example is not included with package and I have configured it like with file backend in named.